Mark the letter A, B, C, or D on your answer sheet to indicate the sentence that is closest in meaning to each of the following questions.

People say that at least ten applicants have been selected for the job interview.

A. It is said that well over ten people are interested in having an interview for the job.

B. It is said that no fewer than ten people are going to be interviewed for the job.

C. People say that fewer than ten job interviews have been held so far.

D. I have heard that only ten people have been chosen to have the job interviewed.

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Diện tích đáy hộp là : 214,8 : 2 = 107,4(cm²)

duyệt nhé

Cây lê ko bao giớ mọc ra táo nên sẽ ko có quả táo nào hết

a. Vì \(\Delta ABC\) vuông tại A

=> \(AB^2+AC^2=BC^2\)

hay \(36^2+48^2=BC^2\)

=> \(\sqrt{BC}=\sqrt{3600}\)

=> BC = 60cm

Xét \(\Delta AHB\) và \(\Delta CAB\) có:

\(\widehat{AHB}=\widehat{CAB}\left(=90^0\right)\)

\(\widehat{B}\left(chung\right)\)

Do đó: \(\Delta AHB\infty\Delta CAB\left(g-g\right)\)

=> \(\dfrac{AH}{AC}=\dfrac{AB}{BC}\)

hay \(\dfrac{AH}{48}=\dfrac{36}{60}\)

=> AH = 28,8 cm

b. Xét \(\Delta CAB\) và \(\Delta CHA\) có:

\(\widehat{CAB}=\widehat{CHA}\left(=90^0\right)\)

\(\widehat{C}\left(chung\right)\)

Do đó: \(\Delta CAB\infty\Delta CHA\left(g-g\right)\)

mà \(\Delta CAB\infty\Delta AHB\left(Cmt\right)\)

=> \(\Delta CHA\infty AHB\)

kết quả là            17    đúng 1000000000000000000% luôn

                          13  

a. Xét \(\Delta HBA\) và \(\Delta ABC\) có:

\(\widehat{B}\left(chung\right)\)

\(\widehat{BHA}=\widehat{BAC}\left(=90^0\right)\)

Do đó: \(\Delta HBA\infty\Delta ABC\left(g-g\right)\)

b. Vì \(\Delta ABC\) vuông tại A
=> \(AB^2+AC^2=BC^2\)

hay \(6^2+8^2=BC^2\)

=> \(\sqrt{BC}=\sqrt{100}\)

=> BC = 10cm

Vì \(\Delta HBA\infty\Delta ABC\left(cmt\right)\)

=> \(\dfrac{AH}{AC}=\dfrac{AB}{BC}\)

hay \(\dfrac{AH}{8}=\dfrac{6}{10}\)

=> AH = 4,8 cm

Vì \(\Delta ABH\) vuông tại H

=> \(BH^2+AH^2=AB^2\)

hay \(BH^2=6-4,8\)

=> BH = 1,2 cm

c. Xét \(\Delta ABC\) và \(\Delta HAC\) có:

\(\widehat{BAC}=\widehat{AHC}\left(=90^0\right)\)

\(\widehat{C}\left(chung\right)\)

Do đó: \(\Delta ABC\infty\Delta HAC\left(g-g\right)\)

Mà \(\Delta HBA\infty\Delta ABC\left(cmt\right)\)

=> \(\Delta HAC\infty\Delta HBA\)

=> \(\dfrac{AH}{HB}=\dfrac{HC}{AH}\)

hay \(AH^2=HB.HC\)

\(\frac{100}{200}=\frac{100:100}{200:100}=\frac{1}{2}\)