a.\(CTHH:\) \(AlCl_3.\)

\(PTK_{AlCl_3}=1\cdot27+3\cdot35,5=133,5đcC.\)

b. \(CTHH:Na_2O.\)

\(PTK:_{Na_2O}=2\cdot23+16=62đvC.\)

\(c.CTHH:KNO_3.\)

\(PTK:_{KNO_3}=39+14+3\cdot16=101đvC.\)

\(d.CTHH:Na_2CO_3.\)

\(PTK:_{Na_2CO_3}=2\cdot23+12+3\cdot16=106đvC.\)

\(e.CTHH:H_2SO_4.\)

\(PTK:_{H_2SO_4}=1\cdot2+56+4\cdot16=122đvC.\)

\(f.CTHH:K_2Cr_2O_7.\)

\(PTK:_{K_2Cr_2O_7}=2\cdot39+2\cdot52+7\cdot16=346đvC.\)

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Bạn chép cho rõ đề ta ạ.

hỗn hợp đầu là gì???

\(a.x^3-6x^2+12x-8=x^3-3.x^2.2+3.x.2^2-2^3\)

\(=\left(x-2\right)^3.\)

\(b.9x^3+12x^2y+6xy^2+y^3\)

Câu b tính kiểu gì dộ.