Cho hàm số \(y=f\left(x\right)=x^2-\dfrac{1}{2x^2}.\) Tính \(f'\left(2\right)-f'\left(-2\right).\)
\(0\).\(8\).\(\dfrac{33}{4}\).\(-1\).Hướng dẫn giải:\(f\left(x\right)=x^2-\dfrac{1}{2x^2}\Rightarrow f'\left(x\right)=2x+\dfrac{1}{x^3}\). Do đó \(f'\left(2\right)=4+\dfrac{1}{8},f'\left(-2\right)=-4-\dfrac{1}{8}\Rightarrow f'\left(2\right)-f'\left(-2\right)=8+\dfrac{1}{4}=\dfrac{33}{4}\)
