\(x^5-3x^4+3x^3-x^2\)
\(=x^2\left(x^3-3x^2+3x-1\right)\)
\(x^2\left(x-1\right)^3\)
x5 - 3x4 + 3x3 - x2 = x2 (x3 - 3x2 + 3x - 1)
Tìm x
b) (x-5) (x-4) - (x+1)(x-2)=7
c) (3x-4)(x-2)=3x(x-9)-3
d)(x-3)(x^2+3x+9)+x(5-x^2)=6x
e) (3x-5)(x+1)-(3x-1)(x+1)=x-4
Tìm x biết:
1. (x-2)^2-(x-3)(x+3)=6
2. 4(x-3)^2-(2x-1)(2x+1)=10
3. (x-4)^2-(x-2)(x+2)=6
4.9(x+1)^2-(3x-2)(3x+2)=10
5. 3x +2(5-x)=0
6.x(2x-1)(x+5)-(2x^2+1)(x+4,5)=3,5
7, 3x^2-3x(x-2)=36
8. (3x^2-x+1)(x-1) +x^2(4-3x)=5/2
Tìm x, biết:
(4x-1)2-(3x+2)(3x-2)= (7x-1)(x+2)+(2x+1)2-(4x2+7)
(5x-1)(x+1)-2(x-3)2= (x+2)(3x-1)-(x+4)2+(x2-x)
(-x+5)(x-2)+(x-7)(x+7)= (3x+1)2-(3x-2)(3x+2)
(2x+3)2-(5x-4)(5x+4)= (x+5)2-(3x-1)(7x+2)-(x2-1)
(1-3x)2-(x-2)(9x+1)= (3x-4)(3x+4)-9(x+3)2
giải pt:
a) x^5 + 2x^4 + 3x^3 + 3x^2 + 2x +1=0
b) x^4 + 3x^3 - 2x^2 + x - 3 = 0
Câu 1. Giải các phườn trình sau:
a, 3x+6=0
b, 2x-10=0
c, 3x-7=11
d, 3x-9=0
e, 3x(2-x) =15(x-2)
f, (x+5)(x+4)=0
g, x(x+4)=0
h, (2x -4)(x-2)=0
i, (x+1/5)(2x-3)=0
k, x²-4x=0
m, 4x²-1=0
n, x²-6x+9=0
l, (3x-5)²-(x+4)²=0
o, 7x(x+2)-5(x+2)=0
p, 3x(2x-5)-4x+10=0
q, (2-2x)-x²+1=0
r, x(1-3x)=5(1-3x)
s, 2x-3/4+x+1/6=3
t, x-3/4-2x+1/3=x/6
u, x+1/13+x+2/12=x+3/11+x+4/10
v, 2x+1/15+2x+2/14=2x+3/13+2x+4/12
Giúp e nha mn. E cảm ơn trc ạ!
\(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
Phân tích các đa thức sau thành nhân tử :
a, x^2 + 4x + 3
b,16x - 5x^2 - 3
c, 2x^2 + 7x + 5
d, 2x^2 + 3x - 5
e,x^3 - 3x^2 + 1 - 3x
f, x^2 - 4x - 5
g, ( a^2 + 1 )^2 - 4a^2
h, x^3 - 3x^2 - 4x + 12
i, x^4 + x^3 + x + 1
k, x^4 - x^3 - x^2 + 1
l, ( 2x + 1 )^2 - ( x - 1 )^2
m,x^4 + 4x^2 - 5
1) x ² + 2x -4 = -12 + 3x + x ²
2) x( 2x - 3 ) - x ² + 2 = x(x - 5) - 1
3) (x-1)(x+3) = x² -4
4) (6x + 2)(x-2) = 2x(3x-5)
5) (x-2) ² = (x-3)(x+2)
Bài 1: giải các phương trình sau
a,(3x-1)(x+3)=(2-x)(5-3x) d,(3x+5)(2x+1)=(6x-2)(x-3)
b,(x+5)(2x-1)=(2x-3)(x+1) e,(x+2)2+2(x-4)=(x-4)(x-2)
c,(x+1)(x+9)=(x+3)(x+5) f,(x+1)(2x-3)-3(x-2)=2(x-1)2
