Question

x^2-y^2/x^2-y^2+xz-yz

Answer 1

\(\dfrac{x^2-y^2}{x^2-y^2+xz-yz}=\dfrac{\left(x-y\right)\left(x+y\right)}{\left(x-y\right)\left(x+y\right)+z\left(x-y\right)}=\dfrac{\left(x-y\right)\left(x+y\right)}{\left(x-y\right)\left(x+y+z\right)}=\dfrac{x+y}{x+y+z}\)