\(\Leftrightarrow x^2=\dfrac{9}{14}\cdot\dfrac{7}{3}=\dfrac{63}{42}=\dfrac{3}{2}\)
hay \(x\in\left\{\dfrac{\sqrt{6}}{2};-\dfrac{\sqrt{6}}{2}\right\}\)
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`x : 9/14 = 7/3 : x`
`=> x^2 = 9/14 xx 7/3`
`=> x^2 = 63/42`
`=> x = +-sqrt(63/42).`
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