Question

tính nồng độ mol/l của ion h  trong mỗi dd sau hòa tan 9.8 g h2so4 vào 400ml dd hno3 2,0M đc 3000ml dd X

Answer 1

\(n_{H_2SO_4}=\dfrac{9,8}{98}=0,1\left(mol\right)\)

\(n_{HNO_3}=0,4.2=0,8\left(mol\right)\)

=> \(\left\{{}\begin{matrix}n_{H^+}=0,1.2+0,8=1\left(mol\right)\\n_{SO_4^{2-}}=0,1\left(mol\right)\\n_{NO_3^-}=0,8\left(mol\right)\end{matrix}\right.\)

=> \(\left\{{}\begin{matrix}n_{H^+}=\dfrac{1}{3}M\\n_{SO_4^{2-}}=\dfrac{0,1}{3}=\dfrac{1}{30}M\\n_{NO_3^-}=\dfrac{0,8}{3}=\dfrac{4}{15}M\end{matrix}\right.\)

Answer 2

n H⁺=0,2+0,8=1 mol

=>CM_X=\(\dfrac{1}{3}\) =0,33M

Answer 3