a: (x-3)(x-5)+|y-2|=0
=>(x-3)(x-5)=0 và y-2=0
hay \(\left(x,y\right)\in\left\{\left(3;2\right);\left(5;2\right)\right\}\)
b: \(\left(x+1\right)\left(3-x\right)=2\left|y\right|+1\)
\(\Leftrightarrow-x^2+3x+3-x-2\left|y\right|-1=0\)
\(\Leftrightarrow-x^2+2x+2-2\left|y\right|=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x^2-2x-2=0\\y=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left(x-1\right)^2=3\\y=0\end{matrix}\right.\Leftrightarrow\left(x,y\right)\in\left\{\left(\sqrt{3}+1;0\right)\left(-\sqrt{3}+1;0\right)\right\}\)
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