Question

Tìm x :

\(\frac{x-2}{5}=\frac{2x-3}{4}\) 

\(\frac{3}{2\left(x-1\right)}=\frac{4}{5\left(x-2\right)}\) 

\(\frac{x-5}{x-6}=\frac{x-1}{x+2}\)

Answer 1

Giải:

Ta có: \(\frac{x-2}{5}=\frac{2x-3}{4}\)

\(\Rightarrow\left(x-2\right).4=5.\left(2x-3\right)\)

\(\Rightarrow4x-8=10x-15\)

\(\Rightarrow4x-10x=8-15\)

\(\Rightarrow-6x=-7\)

\(\Rightarrow x=\frac{7}{6}\)

Vậy \(x=\frac{7}{6}\)

Answer 2

Giải :

Ta có : \(\frac{x-2}{5}=\frac{2x-3}{4}\)

\(\Rightarrow\left(x-2\right),4=5,\left(2x-3\right)\)

\(\Rightarrow4x-8=10x-15\)

\(\Rightarrow4x-10x=8-15\)

\(\Rightarrow-6x=-7\)

\(\Rightarrow x=\frac{7}{6}\)

Vậy \(x\) là \(\frac{7}{6}\)