a) -4x(x-5)-2x(8-2x)=-3
<=> -2x(2x-10+8-2x)=-3
<=> -2x.(-2)=-3
<=> 4x=-3
=> x=\(-\dfrac{3}{4}\)
b)|2x-1|=5
TH1: 2x-1=5
=> 2x=5+1
=> 2x=6
=> x=3
TH2: 2x-1=-5
=> 2x=-5+1
=> 2x=-4
=> x= -2
a, −4x(x−5)−2x(8−2x) = −3
=> \(-4x^2+20x-16x+4x^2=-3\)
=> \(-\left(4x^2-4x^2\right)+\left(20x-16x\right)=-3\)
=> 4x= - 3
=> x = \(\dfrac{-3}{4}\)
b, |2x−1|=5
TH1: 2x-1=5
=> 2x=6
=> x=3
TH2: 2x-1=-5
=> 2x= -4
=> x=-2
a, -4x (x - 5) - 2x (8 - 2x) \(=\) -3
⇒ -4x\(^2\) + 20x + 4x\(^2\) -16x \(=\) -3
⇒ 4x \(=\) -3
⇒ x \(=\) \(\dfrac{-3}{4}\)
b, |2x - 1| \(=\) 5
⇒ 2x - 1 \(=\) 5 hoặc 2x - 1 \(=\) -5
⇒x \(=\) 3 hoặc x \(=\) -1
\(=\)\(=\)