a/
\(3\left(x-2\right)-4\left(2x+1\right)-5\left(2x+3\right)=50\)
\(\Leftrightarrow3x-6-8x-4-10x-15=50\)
\(\Leftrightarrow-15x=50+15+4+6\)
\(\Leftrightarrow-15x=75\Leftrightarrow x=-\dfrac{75}{15}=-5\)
Vậy x = -5
b/ \(\left(x-7\right)^5-\left(x-7\right)^3=0\)
\(\Leftrightarrow\left(x-7\right)^3\left[\left(x-7\right)^2-1\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-7\right)^3=0\\\left(x-7\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-7=0\\\left(x-7\right)^2=1\Rightarrow\left[{}\begin{matrix}x-7=1\\x-7=-1\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\\x=6\end{matrix}\right.\)
Vậy ...........................
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