9(3x - 2) = x(2 - 3x)<=>27x - 18 = 2x - 3x2<=>3x2 +27x - 2x = 18<=> 3x2 +25x - 18= 0<=>3x2 + 27x - 2x -18 = 0<=> 3x(x+9) - 2 (x+9) =0<=> (x+9) (3x-2) = 0\(\Leftrightarrow\left[{}\begin{matrix}x+9=0\\3x-2=0\end{matrix}\right.\Leftrightarrow}\left[{}\begin{matrix}x=-9\\3x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=\dfrac{2}{3}\end{matrix}\right.\) Vậy x=-9 hoặc x= \(\dfrac{2}{3}\)
\(9\left(3x-2\right)=x\left(2-3x\right)\)
\(9\left(3x-2\right)-x\left(2-3x\right)=0\)
\(9\left(3x-2\right)+x\left(3x-2\right)=0\)
\(\left(3x-2\right)\left(9+x\right)=0\)
\(\Rightarrow3x-2=0\) hoặc \(9-x=0\)
*) \(3x-2=0\)
\(3x=2\)
\(x=\dfrac{2}{3}\)
*) \(9+x=0\)
\(x=-9\)
Vậy \(x=\dfrac{2}{3}\); \(x=-9\)