4x2=(x-5)(1-2x)
<=>4x2=x-2x2-5+10x
<=>6x2-11x+5=0
<=>6x2-6x-5x+5=0
<=> 6x(x-1)-5(x-1)=0
<=>(x-1)(6x-5)=0
=>x-1=0 => x=1
hoặc 6x-5=0 => x=5/6
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\(4x^2=\left(x-5\right)\left(1-2x\right)\)
\(4x^2=x-2x^2-5+10x\)
\(4x^2-x+2x^2+5-10x=0\)
\(6x^2-11x+5=0\)
\(6x^2-6x-5x+5=0\)
\(\left(6x^2-6x\right)-\left(5x-5\right)=0\)
\(6x\left(x-1\right)-5\left(x-1\right)=0\)
\(\left(x-1\right)\left(6x-5\right)=0\)
\(x-1=0;6x-5=0\)
*) \(x-1=0\)
\(x=0+1\)
\(x=1\)
*) \(6x-5=0\)
\(6x=0+5\)
\(6x=5\)
\(x=\dfrac{5}{6}\)
Vậy \(x=1;x=\dfrac{5}{6}\)
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