Đặt :
\(A=2x^2-3x+1\)
\(\Rightarrow2A=4x^2-6x+2\)
\(\Rightarrow2A=\left(2x\right)^2-2.2x.\frac{3}{2}+\frac{9}{4}-\frac{5}{4}\)
\(\Rightarrow2A=\left(2x-\frac{3}{2}\right)^2-\frac{5}{4}\)
\(\Rightarrow A=\frac{\left(2x-\frac{3}{2}\right)^2}{2}-\frac{5}{8}\)
\(\Rightarrow A\ge-\frac{5}{8}\)
Dấu " = " xảy ra khi x = 3/4
Vậy MINA= - 5 / 8 khi x = 3 / 4