\(=\dfrac{xy}{2x-y}+\dfrac{2x^2}{2x-y}=\dfrac{2x^2+xy}{2x-y}\)
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Bình luận (1)
\(=\dfrac{xy}{2x-y}+\dfrac{2x^2}{2x-y}=\dfrac{2x^2+xy}{2x-y}\)