Violympic toán 9
Các câu hỏi tương tự
BL
30 tháng 11 2019 lúc 22:18
Giải pt : a) \(8x^2-13x+7=\left(1+\frac{1}{x}\right)\sqrt[3]{3x^2-2}\)
b) \(\sqrt{4x^2+5x+1}-2\sqrt{x^2-x+1}=9x-3\)
c) \(2\sqrt{x+1}+6\sqrt{9-x^2}+6\sqrt{\left(x+1\right)\left(9-x^2\right)}=38+10x-2x^2-x^3\)
Giải phương trình:
1, \(8x^3-13x+7=\left(x+1\right)\sqrt[3]{3x^2-2}\)
2, \(9+3\sqrt{x\left(3-2x\right)}=7\sqrt{x}+5\sqrt{3-2x}\)
3, \(x^3-\sqrt[3]{6+\sqrt[3]{x+6}}=6\)
Giải phương trình: \(\sqrt{x^2+x+19}+\sqrt{7x^2-2x+4}+\sqrt{13x^2+19x+7}=\sqrt{3}.\left(x+5\right)\)
NC
14 tháng 1 2021 lúc 12:59
Giải phương trình 1, \(x^2+9x+7=\left(2x+1\right)\sqrt{2x^2+4x+5}\)
2, GPT \(\left(2x+7\right)\sqrt{2x+7}=x^2+9x+7\)
3. GHPT \(\left\{{}\begin{matrix}x^2-2y-1=2\sqrt{5y+8}+\sqrt{7x-1}\\\left(x-y\right)\left(x^2+xy+y^2+3\right)=3\left(x^2+y^2\right)+2\end{matrix}\right.\)
a. sqrt{1-2x}x+7
b.sqrt{1+x^2}2x-1
c.sqrt{1-x}-sqrt{2+x}1
d. sqrt{1-x}+sqrt{4+x}3
e. left|2x+5right| x-1
f. left|xright|+left|2x-1right|x+2
g.left|x-9right|^{10}+left|x-10right|^{10}1
h. left|x-2014right|^{2015}+left|x-2015right|^{2014}1
i. sqrt{x+3+4sqrt{x-1}}+sqrt{x+8-6sqrt{x-1}}5
k. sqrt{x+2sqrt{x-1}}+sqrt{x-2sqrt{x-1}}x-1
l. sqrt{x+2-4sqrt{x-2}}+sqrt{x+7-6sqrt{x-2}}1
m. sqrt{x+8+2sqrt{x+7}}+sqrt{x-1-2sqrt{x+7}}4
m. x+sqrt{x+frac{1}{4}+sqrt{x+frac{1}{4}}}frac{9}{4}
n.left(x+5righ...
Đọc tiếp
a. \(\sqrt{1-2x}=x+7\)
b.\(\sqrt{1+x^2}=2x-1\)
c.\(\sqrt{1-x}-\sqrt{2+x}=1\)
d. \(\sqrt{1-x}+\sqrt{4+x}=3\)
e. \(\left|2x+5\right|\)= x-1
f. \(\left|x\right|+\left|2x-1\right|=x+2\)
g.\(\left|x-9\right|^{10}+\left|x-10\right|^{10}=1\)
h. \(\left|x-2014\right|^{2015}+\left|x-2015\right|^{2014}=1\)
i. \(\sqrt{x+3+4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=5\)
k. \(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=x-1\)
l. \(\sqrt{x+2-4\sqrt{x-2}}+\sqrt{x+7-6\sqrt{x-2}}=1\)
m. \(\sqrt{x+8+2\sqrt{x+7}}+\sqrt{x-1-2\sqrt{x+7}}=4\)
m. \(x+\sqrt{x+\frac{1}{4}+\sqrt{x+\frac{1}{4}}}=\frac{9}{4}\)
n.\(\left(x+5\right)^4+\left(x+7\right)^4=2\)
Giải pt
Giải hệ pt
1/left{{}begin{matrix}4xsqrt{y+1}+8xleft(4x^2-4x-3right)sqrt{x+1}dfrac{x}{x+1}+x^2left(y+2right)sqrt{left(x+1right)left(y+1right)}end{matrix}right.
2/left{{}begin{matrix}xsqrt{y^2+6}+ysqrt{x^2+3}7xyxsqrt{x^2+3}+ysqrt{y^2+6}x^2+y^2+2end{matrix}right.left{{}begin{matrix}xsqrt{y^2+6}+ysqrt{x^2+3}7xyxsqrt{x^2+3}+ysqrt{y^2+6}x^2+y^2+2end{matrix}right.
3/left{{}begin{matrix}left(2x+y-1right)left(sqrt{x+3}+sqrt{xy}+sqrt{x}right)8sqrt{x}left(sqrt{x+3}+sqrt{xy}right)^2+xy2xleft(6-xright)end...
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Giải hệ pt
1/\(\left\{{}\begin{matrix}4x\sqrt{y+1}+8x=\left(4x^2-4x-3\right)\sqrt{x+1}\\\dfrac{x}{x+1}+x^2=\left(y+2\right)\sqrt{\left(x+1\right)\left(y+1\right)}\end{matrix}\right.\)
2/\(\left\{{}\begin{matrix}x\sqrt{y^2+6}+y\sqrt{x^2+3}=7xy\\x\sqrt{x^2+3}+y\sqrt{y^2+6}=x^2+y^2+2\end{matrix}\right.\)\(\left\{{}\begin{matrix}x\sqrt{y^2+6}+y\sqrt{x^2+3}=7xy\\x\sqrt{x^2+3}+y\sqrt{y^2+6}=x^2+y^2+2\end{matrix}\right.\)
3/\(\left\{{}\begin{matrix}\left(2x+y-1\right)\left(\sqrt{x+3}+\sqrt{xy}+\sqrt{x}\right)=8\sqrt{x}\\\left(\sqrt{x+3}+\sqrt{xy}\right)^2+xy=2x\left(6-x\right)\end{matrix}\right.\)\(\left\{{}\begin{matrix}\left(2x+y-1\right)\left(\sqrt{x+3}+\sqrt{xy}+\sqrt{x}\right)=8\sqrt{x}\\\left(\sqrt{x+3}+\sqrt{xy}\right)^2+xy=2x\left(6-x\right)\end{matrix}\right.\)
4/\(\left\{{}\begin{matrix}\sqrt{xy+x+2}+\sqrt{x^2+x}-4\sqrt{x}=0\\xy+x^2+2=x\left(\sqrt{xy+2}+3\right)\end{matrix}\right.\)\(\left\{{}\begin{matrix}\sqrt{xy+x+2}+\sqrt{x^2+x}-4\sqrt{x}=0\\xy+x^2+2=x\left(\sqrt{xy+2}+3\right)\end{matrix}\right.\)
m.n giúp e mấy bài này vs ạ!!
1\(\left\{{}\begin{matrix}xy\left(x+y\right)=2\\x^3+y^3+x^3y^3+7\left(x+1\right)\left(y+1\right)=31\end{matrix}\right.\)
2 giải pt \(9+3\sqrt{x\left(3-2x\right)}=7\sqrt{x}+5\sqrt{3-2x}\)
Giải các phương trình sau:
1. sqrt{x^2-dfrac{1}{4}+sqrt{x^2+x+dfrac{1}{4}}}dfrac{1}{2}left(2x^3+x^2+2x+1right)
2. x^2+4x+7left(x+4right)sqrt{x^2+7}
3. sqrt{x-1}+sqrt{x^3+x^2+x+1}1+sqrt{x^4-1}
4. sqrt{x^2-3x+2}+sqrt{x+3}sqrt{x-2}+sqrt{x^2+2x-3}
5. xleft(sqrt{x}+2right)left(1-sqrt{1-sqrt{x}}right)
6. 2sqrt[3]{2x-1}x^3+1
7. sqrt{x-dfrac{1}{x}}+sqrt{1-dfrac{1}{x}}x
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Giải các phương trình sau:
1. \(\sqrt{x^2-\dfrac{1}{4}+\sqrt{x^2+x+\dfrac{1}{4}}}=\dfrac{1}{2}\left(2x^3+x^2+2x+1\right)\)
2. \(x^2+4x+7=\left(x+4\right)\sqrt{x^2+7}\)
3. \(\sqrt{x-1}+\sqrt{x^3+x^2+x+1}=1+\sqrt{x^4-1}\)
4. \(\sqrt{x^2-3x+2}+\sqrt{x+3}=\sqrt{x-2}+\sqrt{x^2+2x-3}\)
5. \(x=\left(\sqrt{x}+2\right)\left(1-\sqrt{1-\sqrt{x}}\right)\)
6. \(2\sqrt[3]{2x-1}=x^3+1\)
7. \(\sqrt{x-\dfrac{1}{x}}+\sqrt{1-\dfrac{1}{x}}=x\)
BL
25 tháng 4 2020 lúc 11:56
Gpt: a) sqrt[4]{3left(x+5right)}-sqrt[4]{11-x}sqrt[4]{13+x}-sqrt[4]{3left(3-xright)}
b) frac{1+2sqrt{x}-xsqrt{x}}{3-x-sqrt{2-x}}2left(frac{1+xsqrt{x}}{1+x}right) c) sqrt{x+1}+frac{4left(sqrt{x+1}+sqrt{x-2}right)}{3left(sqrt{x-2}+1right)^2}3
d) sqrt{frac{x-2}{x+1}}+frac{x+2}{left(sqrt{x+2}+sqrt{x-2}right)^2}1 e) 2x+1+xsqrt{x^2+2}+left(x+1right)sqrt{x^2+2x+2}0
f) sqrt{2x+3}cdotsqrt[3]{x+5}x^2+x-6
Đọc tiếp
Gpt: a) \(\sqrt[4]{3\left(x+5\right)}-\sqrt[4]{11-x}=\sqrt[4]{13+x}-\sqrt[4]{3\left(3-x\right)}\)
b) \(\frac{1+2\sqrt{x}-x\sqrt{x}}{3-x-\sqrt{2-x}}=2\left(\frac{1+x\sqrt{x}}{1+x}\right)\) c) \(\sqrt{x+1}+\frac{4\left(\sqrt{x+1}+\sqrt{x-2}\right)}{3\left(\sqrt{x-2}+1\right)^2}=3\)
d) \(\sqrt{\frac{x-2}{x+1}}+\frac{x+2}{\left(\sqrt{x+2}+\sqrt{x-2}\right)^2}=1\) e) \(2x+1+x\sqrt{x^2+2}+\left(x+1\right)\sqrt{x^2+2x+2}=0\)
f) \(\sqrt{2x+3}\cdot\sqrt[3]{x+5}=x^2+x-6\)