-đề sai rồi. sửa lại nhé:
A=\(\dfrac{x^5+x^2}{x^3-x^2+x}\)
=\(\dfrac{x^2\left(x^3+1\right)}{x\left(x^2-x+1\right)}\)
=\(\dfrac{x\left(x^3+1^3\right)}{x^2-x+1}\)
=\(\dfrac{x\left(x+1\right)\left(x^2-x+1\right)}{(x^2-x+1)}\)
=\(x\left(x+1\right)\)