Question

Phân tích đa thức thành nhân tử

1) 27+27x+9x²+x³ 2) 8 - 27x³

3) x⁶⁴ + x³² + 1

Answer 1

1) \(27+27x+9x^2+x^3\)

\(=3^3+3.3^2.x+3.3.x^2+x^3\)

\(=\left(3+x\right)^3\)

2) \(8-27x^3\)

\(=2^3-\left(3x\right)^3\)

\(=\left(2-3x\right)\left[2^2+2.3x+\left(3x\right)^2\right]\)

\(=\left(2-3x\right)\left(4+6x+9x^2\right)\)

Answer 2

\(1,27+27+9x^2+x^3\)

\(=\left(3+x\right)^3\)

\(2,8-27x^3\)

\(=\left(2-3x\right).\left(4+6x+9x^2\right)\)

\(3,x^{64}+x^{32}+1\)

\(=\left(x^{64}+2x^{32}+1\right)-x^{32}\)

\(=\left(x^{32}+1\right)^2-x^{32}\)

\(=\left(x^{32}+1-x^{16}\right).\left(x^{32}+1+x^{16}\right)\)

Công nhận câu 3 hơi căng~