\(\dfrac{9}{10}cm=\dfrac{9}{10}cm\)
\(\dfrac{4}{5}cm=\dfrac{8}{10}cm\)
\(\dfrac{3}{2}cm=\dfrac{15}{10}cm\)
\(\dfrac{6}{5}cm=\dfrac{12}{10}cm\)
\(\dfrac{1}{2}cm=\dfrac{5}{10}cm\)
mà 15>12>9>8>5
nên \(\dfrac{3}{2}cm>\dfrac{6}{5}cm>\dfrac{9}{10}cm>\dfrac{4}{5}cm>\dfrac{1}{2}cm\)
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\(\dfrac{1}{2}< \dfrac{4}{5}< \dfrac{9}{10}< \dfrac{6}{5}< \dfrac{3}{2}\)
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\(\dfrac{9}{10};\dfrac{4}{5}=\dfrac{8}{10};\dfrac{3}{2}=\dfrac{15}{10};\dfrac{6}{5}=\dfrac{12}{10};\dfrac{1}{2}=\dfrac{5}{10}\)
-> Sắp xếp: \(\dfrac{3}{2};\dfrac{6}{5};\dfrac{9}{10};\dfrac{4}{5};\dfrac{1}{2}\)
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