Lời giải:
ĐKXĐ: $x>0; x\neq 1$
\(\left(\frac{\sqrt{x}}{\sqrt{x}-1}+\frac{1}{\sqrt{x}-x}\right):\left(\frac{1}{\sqrt{x}+1}-\frac{2}{1-\sqrt{x}}\right)=\left(\frac{x}{x-\sqrt{x}}-\frac{1}{x-\sqrt{x}}\right):\frac{1-\sqrt{x}-2\sqrt{x}-2}{(\sqrt{x}+1)(1-\sqrt{x})}\)
\(=\frac{x-1}{x-\sqrt{x}}:\frac{-(1+3\sqrt{x})}{1-x}=\frac{x-1}{x-\sqrt{x}}.\frac{x-1}{3\sqrt{x}+1}=\frac{(x-1)^2}{(x-\sqrt{x})(3\sqrt{x}+1)}\)
1. Rút gọn
P=\(2\sqrt{1+\frac{1}{4}\left(\sqrt{\frac{1}{x}}-\sqrt{x}\right)^2}:\left[\sqrt{1+\frac{1}{4}\left(\sqrt{\frac{1}{x}}-\sqrt{x}\right)^2}-\frac{1}{2}\left(\sqrt{\frac{1}{x}}-\sqrt{x}\right)^2\right]\)
RG
A = \(\left(\frac{1}{x-\sqrt{x}}+\frac{1}{\sqrt{x}-1}\right):\frac{\sqrt{x}+1}{x-2\sqrt{x}+1}\)
B = \(\left(\frac{\sqrt{x}-2}{x-1}-\frac{\sqrt{x}+2}{x+2\sqrt{x}+1}\right).\left(\frac{1-x}{\sqrt{2}}\right)^2\)
P=\(\left(\frac{1}{\sqrt{x}-1}-\frac{1}{\sqrt{x}}\right):\left(\frac{\sqrt{x}+1}{\sqrt{x}-2}-\frac{\sqrt{x}+2}{\sqrt{x}-1}\right)\)
Rút gọn A = \(1-\left(\frac{2x-1+\sqrt{x}}{1-x}+\frac{2x\sqrt{x}+x-\sqrt{x}}{1+x\sqrt{x}}\right).\left(\frac{\left(x-\sqrt{x}\right)\left(1-\sqrt{x}\right)}{2\sqrt{x}-1}\right)\)
\(\left(\frac{1}{\sqrt{x}-\sqrt{x-1}}-\frac{x-3}{\sqrt{x-1}-\sqrt{2}}\right)\left(\frac{2}{\sqrt{2}-\sqrt{x}}-\frac{\sqrt{x}+\sqrt{2}}{\sqrt{2x}-x}\right)\)
\(P=\frac{x\sqrt{x}-1}{x-\sqrt{x}}-\frac{x\sqrt{x}+1}{x+\sqrt{x}}+\left(\sqrt{x}-\frac{1}{\sqrt{x}}\right)\left(\frac{\sqrt{x}+1}{\sqrt{x-1}}+\frac{\sqrt{x}-1}{\sqrt{x}+1}\right)-2\sqrt{x}\)
rút gọn P
Rút gọn: \(P=1-\left(\frac{2x-1+\sqrt{x}}{1-x}+\frac{2x\sqrt{x}+x-\sqrt{x}}{1+x\sqrt{x}}\right).\frac{\left(x-\sqrt{x}\right)\left(1-\sqrt{x}\right)}{2\sqrt{x}-1}\)
Cho biểu thức A= \(\left(\frac{1}{\sqrt{x-1}}-\frac{1}{\sqrt{x}}\right):\left(\frac{\sqrt{x}+1}{\sqrt{x-2}}-\frac{\sqrt{x}+2}{\sqrt{x}-1}\right)\)
\(\left(\frac{1}{\sqrt{x-1}}+\frac{\sqrt{x}}{\sqrt{x-1}}\right):\frac{\sqrt{x+1}}{\left(\sqrt{x-1}\right)^2}\)