a) \(PTK_{Cl_2}\\ =2.NTK_{Cl}\\ =2.35,5\\ =71\left(đvC\right)\)
b) \(PTK_{H_2SO_4}\\ =2.NTK_H+NTK_S+4.NTK_O\\ =2.1+32+4.16\\ =98\left(đvC\right)\)
c) \(PTK_{KMnO_4}\\ =NTK_K+NTK_{Mn}+4.NTK_O\\ =39+55+4.16\\ =158\left(đvC\right)\)
a, PTK của Cl2: 2.35,5=71 đvC
b, PTK của H2SO4: 2.1+32+4.16=98 đvC
c, PTK của KMnO4: 39+55+4.16=158 đvC
a) PTKCl2 = \(35,5\cdot2=71\left(\text{đ}vC\right)\)
b) PTKH2SO4 = \(1\cdot2+32+16\cdot4=98\left(\text{đ}vC\right)\)
c) PTKKMnO4 = \(39+55+16\cdot4=158\left(\text{đ}vC\right)\)
a) PTKCl2=2.NTKCl=2.35,5=71(đvC)PTKCl2=2.NTKCl=2.35,5=71(đvC)
b) PTKH2SO4=2.NTKH+NTKS+4.NTKO=2.1+32+4.16=98(đvC)PTKH2SO4=2.NTKH+NTKS+4.NTKO=2.1+32+4.16=98(đvC)
c) PTKKMnO4=NTKK+NTKMn+4.NTKO=39+55+4.16=158(đvC)PTKKMnO4=NTKK+NTKMn+4.NTKO=39+55+4.16=158(đvC)