Question

giải pt

\(\dfrac{2x}{3}\) - \(\dfrac{x+1}{5}\) = 2 + \(\dfrac{x-3}{2}\)

Answer 1

\(\Leftrightarrow20x-6\left(x+1\right)=60+15\left(x-3\right)\)

=>20x-6x-6=60+15x-45

=>15x+15=14x-6

=>x=-21

Answer 2

`<=> (20x)/30 - (6x + 6)/30 = 60/30 + (30x - 90)/30`

`<=> (14x - 6)/30 = (30x - 30)/30`

`=> (7x - 3)/10 = (10x-10)/10`

`=> 7x - 3 = 10x - 10`

`=> 13 = 3x`

`=> x = 13/3`

Answer 3

\(\Leftrightarrow\dfrac{20x}{30}-\dfrac{6\left(x+1\right)}{30}=\dfrac{60}{30}+\dfrac{15\left(x-3\right)}{30}\)

\(\Leftrightarrow20x-6x-6-60-15x+45=0\)

<=>-9 -x = 0

<=> x = -9 - 0 = -9

=> x = - 9 

Answer 4

<=> \(\dfrac{10.2x}{30}\) - \(\dfrac{6\left(x+1\right)}{30}\) = \(\dfrac{30.2}{30}\) + \(\dfrac{15\left(x-3\right)}{30}\)
<=> 20x - 6x - 6 = 60 +15x - 45
<=> 20x - 6x - 6 - 60 - 15 + 45 = 0
<=> - x - 21 = 0
<=> - x    = 21
<=>   x    = -21
Vậy S = \(\left\{-21\right\}\)