Phương trình bậc nhất một ẩn
Các câu hỏi tương tự
giải các pt:
1, 3-x/27 + 3-x/28 = x-3/29 + 3-x/30
2, 1/x+2 - 6/x-1 + 8/x2+x-2 =0
3, x+2/x+3 - x+1/x-1 = 4/x2 + 2x-3
đang gấp, giúp e với ạ
bài 1: giải các pt sau: a, 1/x-2+3=7-x/x-2
b, x^2-x/x+3-x^2/x-3=7x^2-3x/9-x^2
c, x/2x-1 + x+1/x+2=0
d, 2/x+1 - 1/x-2 = 3x-11/(x+1)(x-2)
Bài1: giải các pt sau:
a, 3-4x+24+6x= x+27+3x
b, 5-(6-x)=4(3-2x)
c, x-(x+1)/3 = (2x+1)/5
d,(2x-1)/3 - (5x+2)/7 = x+13
Bài 2:
a, (x-1)(3x+1)=0
b, (x-5)(7-x)=0
c, ( x-1)(x+5)(-3x+8)=0
d, x(x^2 - 1 )=0
Giúp mình 2 bài này với , mình đang cần gấp , CẢM ƠN M.N ạ><
Giải pt sau:
1) (9x2-4)(x+1)(3x+2)(x2-1)
2) (x-1)2-1+x2(1-x)(x+3)
3) x2-7x+60
4) x4 -4x3+12-90
5) (x2+x)2+4(x2+x)-120
6) x(x+1)(x2+x+1)42
7) (x+2)(x-2)(x2-10)72
8) (x-1)(x-3)(x+5)(x+7)-2970
9) 4(2x+7)2-9(x+3)20
10) x4-2x2-144x-12950
Đọc tiếp
Giải pt sau:
1) (9x2-4)(x+1)=(3x+2)(x2-1)
2) (x-1)2-1+x2=(1-x)(x+3)
3) x2-7x+6=0
4) x4 -4x3+12-9=0
5) (x2+x)2+4(x2+x)-12=0
6) x(x+1)(x2+x+1)=42
7) (x+2)(x-2)(x2-10)=72
8) (x-1)(x-3)(x+5)(x+7)-297=0
9) 4(2x+7)2-9(x+3)2=0
10) x4-2x2-144x-1295=0
1. giải pt :
a) \(\dfrac{1}{x-3}+2=\dfrac{5}{x-1}+x\)
b)\(\dfrac{2}{x^2+4x-21}=\dfrac{3}{x-3}\)
c) \(\dfrac{1}{x^2+2x+3}+4=\dfrac{1}{x^2+1}\)
d) \(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}=\dfrac{8}{4x^2-1}\)
e) \(\dfrac{3x-1}{x-1}-\dfrac{2x+5}{x+3}+\dfrac{4}{x^2+2x-3}=1\)
1) giải pt :
a) dfrac{x-5}{100}+dfrac{x-4}{101}+dfrac{x-3}{102}dfrac{x-100}{5}+dfrac{x-101}{4}+dfrac{x-102}{3}
b) dfrac{29-x}{21}+dfrac{27-x}{23}+dfrac{25-x}{25}+dfrac{23-x}{27}+dfrac{21-x}{29}-5
2) giải pt :
a) left(5x+1right)^2left(3x-2right)^2
b) left(x+2right)^3left(2x+1right)^3
c) left(x+3right)^4+left(x+5right)^42
d) x^4-3x^3+4x^2-3x+10
Đọc tiếp
1) giải pt :
a) \(\dfrac{x-5}{100}+\dfrac{x-4}{101}+\dfrac{x-3}{102}=\dfrac{x-100}{5}+\dfrac{x-101}{4}+\dfrac{x-102}{3}\)
b) \(\dfrac{29-x}{21}+\dfrac{27-x}{23}+\dfrac{25-x}{25}+\dfrac{23-x}{27}+\dfrac{21-x}{29}=-5\)
2) giải pt :
a) \(\left(5x+1\right)^2=\left(3x-2\right)^2\)
b) \(\left(x+2\right)^3=\left(2x+1\right)^3\)
c) \(\left(x+3\right)^4+\left(x+5\right)^4=2\)
d) \(x^4-3x^3+4x^2-3x+1=0\)
\(\dfrac{x^2+2x+2}{^{ }x+1}+\dfrac{x^2+8x+20}{x+4}=\dfrac{x^2+4x+6}{x+2}+\dfrac{x^2+6x+12}{x+3}\)
giải pt
bài 1:giải các pt sau:
a/frac{1-x}{x+1}+3frac{2x+3}{x+1}
b/frac{left(x+2right)^2}{2x-3}-1frac{x^2+10}{2x-3}
c/frac{1}{x+1}-frac{5}{x-2}frac{15}{left(x+1right)left(2-xright)}
d/frac{1-6x}{x-2}+frac{9x+4}{x+2}frac{xleft(3x-2right)+1}{x^2-4}
e/frac{12}{1-9x^2}frac{1-3x}{1+3x}-frac{1+3x}{1-3x}
ffrac{x+4}{x^2-3x+2}+frac{x+1}{x^2-4x+3}frac{2x+5}{x^2-4x+3}
Đọc tiếp
bài 1:giải các pt sau:
a/\(\frac{1-x}{x+1}\)+3=\(\frac{2x+3}{x+1}\)
b/\(\frac{\left(x+2\right)^2}{2x-3}-1=\frac{x^2+10}{2x-3}\)
c/\(\frac{1}{x+1}-\frac{5}{x-2}=\frac{15}{\left(x+1\right)\left(2-x\right)}\)
d/\(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{x^2-4}\)
e/\(\frac{12}{1-9x^2}=\frac{1-3x}{1+3x}-\frac{1+3x}{1-3x}\)
f\(\frac{x+4}{x^2-3x+2}+\frac{x+1}{x^2-4x+3}=\frac{2x+5}{x^2-4x+3}\)
Giải các PT sau :
a,frac{1-6x}{x-2}+frac{9x+4}{x+2}frac{xleft(3x-2right)+1}{left(x+2right)left(x-2right)}
b,(2 - 3x) (x + 11) (3x - 2) (2 - 5x)
c,frac{3x-2}{6}-5frac{3-2left(x+7right)}{4}
d,frac{x}{x-3}+frac{x}{x
+1}frac{2x}{left(x+1right)left(x-3right)}
e,frac{x+1}{5}+frac{x+2}{4}frac{x+3}{3}+frac{x+4}{2}
Đọc tiếp
Giải các PT sau :
a,\(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{\left(x+2\right)\left(x-2\right)}\)
b,(2 - 3x) (x + 11) = (3x - 2) (2 - 5x)
c,\(\frac{3x-2}{6}-5=\frac{3-2\left(x+7\right)}{4}\)
d,\(\frac{x}{x-3}+\frac{x}{x +1}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
e,\(\frac{x+1}{5}+\frac{x+2}{4}=\frac{x+3}{3}+\frac{x+4}{2}\)