Question

Giải pt sau:

|2x-5|+|2x²-7x+5|=0

Answer 1

\(\left|2x-5\right|+\left|2x^2-7x+5\right|=0\)

\(\left\{{}\begin{matrix}2x-5=0\\2x^2-7x+5=0\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}2x-5=0\\\left(2x-5\right)\left(x-1\right)=0\end{matrix}\right.\)

\(\Leftrightarrow x=\dfrac{5}{2}\)

Answer 2

 

{2x−5=02x2−7x+5=0⇔{2x−5=0(2x−5)(x−1)=0