Question

Giải pt :

\(2\sqrt{x^6+1}=3\left(x^4+2\right)\)

Answer 1

\(\Leftrightarrow2\sqrt{\left(x^2+1\right)\left(x^4-x^2+1\right)}=3\left(x^4+2\right)\)

Đặt \(\left\{{}\begin{matrix}\sqrt{x^4-x^2+1}=a>0\\\sqrt{x^2+1}=b>0\end{matrix}\right.\)

\(\Rightarrow2ab=3\left(a^2+b^2\right)\)

\(\Leftrightarrow2\left(a^2+b^2\right)+\left(a-b\right)^2=0\)

Pt vô nghiệm