\(x\ge-3\)
\(x^4\left(\sqrt{x+3}-2\right)+2016\left(x-1\right)=0\)
\(\Leftrightarrow\dfrac{x^4\left(x-1\right)}{\sqrt{x+3}+2}+2016\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(\dfrac{x^4}{\sqrt{x+3}+2}+2016\right)=0\)
\(\Leftrightarrow x-1=0\) (do \(\dfrac{x^4}{\sqrt{x+3}+2}+2016>0\) \(\forall x\ge-3\) )
\(\Rightarrow x=1\)
Vậy pt có nghiệm duy nhất \(x=1\)