Đặt \(\left\{{}\begin{matrix}\sqrt[3]{x-1}=a\\\sqrt[3]{x-2}=b\end{matrix}\right.\) \(\Rightarrow a^3+b^3=2x-3\)
\(\Rightarrow a+b=\sqrt[3]{a^3+b^3}\)
\(\Leftrightarrow a^3+b^3+3ab\left(a+b\right)=a^3+b^3\)
\(\Leftrightarrow ab\left(a+b\right)=0\Rightarrow\left[{}\begin{matrix}a=0\\b=0\\a=-b\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x-1=0\\x-2=0\\\sqrt[3]{x-1}=\sqrt[3]{2-x}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=1\\x=2\\x=\frac{3}{2}\end{matrix}\right.\)