Question

Giải phương trình sau:

\(\dfrac{5x-2}{2-2x}+\dfrac{2x-1}{2}=1-\dfrac{x^2+x-3}{1-x}\)

Answer 1

ĐKXĐ : x khác 1

\(\dfrac{5x-2}{2-2x}+\dfrac{2x-1}{2}=1-\dfrac{x^2+x-3}{1-x}\)

\(\Leftrightarrow\dfrac{5x-2}{2\left(1-x\right)}+\dfrac{\left(2x-1\right)\left(1-x\right)}{2\left(1-x\right)}=\dfrac{2\left(1-x\right)}{2\left(1-x\right)}-\dfrac{2\left(x^2+x-3\right)}{2\left(1-x\right)}\)

\(\Rightarrow5x-2+x-2x^2-1=2-2x-2x^2-2x+6\)

\(\Leftrightarrow9x-9=0\)

\(\Leftrightarrow x=1\left(loại\right)\)

Vậy pt vô nghiệm