Chắc là bạn ghi nhầm đề
\(5\left(x^2+y^2\right)=5xy\Leftrightarrow x^2+y^2-xy=0\)
\(\Leftrightarrow\left(x-\frac{y}{2}\right)^2+\frac{3y^2}{4}=0\Leftrightarrow\left\{{}\begin{matrix}x-\frac{y}{2}=0\\y=0\end{matrix}\right.\) \(\Rightarrow x=y=0\)
Thay lên pt trên ko thỏa mãn nên hệ vô nghiệm
giải các hệ phương trình sau
1\(\left\{{}\begin{matrix}\left(x-1\right)-\left(x+2\right)^2=9y\\\left(y-3\right)^2-\left(y+2\right)^2=5x\end{matrix}\right.\)
2 \(\left\{{}\begin{matrix}\left(7+x\right)^2-\left(5+x\right)^2=6y\\\left(2-y\right)^2-\left(6-y\right)^2=4x\end{matrix}\right.\)
3) \(\left\{{}\begin{matrix}\left(x+1\right)^2+\left(y-2\right)^2=x^2+y^2\\\left(x-3\right)^2+\left(y+1\right)^2=x^2-x+y^3-3\end{matrix}\right.\)
Giải hệ phương trình:
a)\(\left\{{}\begin{matrix}\left(x+2\right)\left(y-2\right)=xy\\\left(x+4\right)\left(y-3\right)=xy+6\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\left(x+5\right)\left(y-2\right)=xy\\\left(x-5\right)\left(y+12\right)=xy\end{matrix}\right.\)
Giải hệ phương trình
1. \(\left\{{}\begin{matrix}x^2+y^2+2x+2y=\left(x+2\right)\left(y+2\right)\\\left(\frac{x}{y+2}\right)^2+\left(\frac{y}{x+2}\right)^2=1\end{matrix}\right.\)
2. \(\left\{{}\begin{matrix}x^2-2xy-6=6y+2x\\\frac{3x^2}{y+1}=4-x\end{matrix}\right.\)
3.\(\left\{{}\begin{matrix}x^2-y=y^2-x\\x^2-x=y+3\end{matrix}\right.\)
4.\(\left\{{}\begin{matrix}x+y+\frac{1}{x}+\frac{1}{y}=\frac{9}{2}\\xy+\frac{1}{xy}+\frac{x}{y}+\frac{y}{x}=5\end{matrix}\right.\)
6.\(\left\{{}\begin{matrix}x^3\left(x-y\right)+x^2y^2=1\\x^2\left(xy+3\right)-3xy=3\end{matrix}\right.\)
7.\(\left\{{}\begin{matrix}x^2+3y-6x=0\\9x^2-6xy^2+y^4-3y+9=0\end{matrix}\right.\)
8.\(\left\{{}\begin{matrix}x^2+y^2+xy=1\\x+y-xy=2y^2-x^2\end{matrix}\right.\)
9.\(\left\{{}\begin{matrix}8x^3-y=y^3-2x\\x^2+y^2=x+2y\end{matrix}\right.\)
10.\(\left\{{}\begin{matrix}2x^2-3xy+y^2+x-y=0\\x^2+x+1=y^2\end{matrix}\right.\)
11.\(\left\{{}\begin{matrix}\left(x^2+y^2\right)\left(x+y+2\right)=4\left(y+2\right)\\x^2+y^2+\left(y+2\right)\left(x+y+2\right)=4\left(y+2\right)\end{matrix}\right.\)
12. \(\left\{{}\begin{matrix}x^2+7=4y^2+4y\\x^2+3xy+2y^2+x+y=0\end{matrix}\right.\)
13. \(\left\{{}\begin{matrix}x^2+y^2=5\\x^3+2y^3+\left(x-5\right)^2+\left(y+5\right)^2=55\end{matrix}\right.\)
14. \(\left\{{}\begin{matrix}\frac{1}{x^2}+\frac{1}{y^2}=3+x^2y^2\\\frac{1}{x^3}+\frac{1}{y^3}+3=x^3y^3\end{matrix}\right.\)
15.\(\left\{{}\begin{matrix}x^2+y^2+4x+2y=3\\x^2+7y^2-4xy+6y=13\end{matrix}\right.\)
16. \(\left\{{}\begin{matrix}x^2-5xy+x-5y^2=42\\7xy+6y^2+42=x\end{matrix}\right.\)
17.\(\left\{{}\begin{matrix}x^2+xy+y^2=13\\x^4+x^2y^2+y^4=91\end{matrix}\right.\)
18.\(\left\{{}\begin{matrix}x^2=\left(2-y\right)\left(2+y\right)\\2x^3=\left(x+y\right)\left(4-xy\right)\end{matrix}\right.\)
Đây là các bài hệ trong đề thi chuyên toán mong mọi người giúp vì mình bận quá nên không thể làm hết được ạ
Giải hệ phương trình:
1. \(\left\{{}\begin{matrix}x+3=2\sqrt{\left(3y-x\right)\left(y+1\right)}\\\sqrt{3y-2}-\sqrt{\dfrac{x+5}{2}}=xy-2y-2\end{matrix}\right.\)
2. \(\left\{{}\begin{matrix}\sqrt{2y^2-7y+10-x\left(y+3\right)}+\sqrt{y+1}=x+1\\\sqrt{y+1}+\dfrac{3}{x+1}=x+2y\end{matrix}\right.\)
3. \(\left\{{}\begin{matrix}\sqrt{4x-y}-\sqrt{3y-4x}=1\\2\sqrt{3y-4x}+y\left(5x-y\right)=x\left(4x+y\right)-1\end{matrix}\right.\)
4. \(\left\{{}\begin{matrix}9\sqrt{\dfrac{41}{2}\left(x^2+\dfrac{1}{2x+y}\right)}=3+40x\\x^2+5xy+6y=4y^2+9x+9\end{matrix}\right.\)
5. \(\left\{{}\begin{matrix}\sqrt{xy+\left(x-y\right)\left(\sqrt{xy}-2\right)}+\sqrt{x}=y+\sqrt{y}\\\left(x+1\right)\left[y+\sqrt{xy}+x\left(1-x\right)\right]=4\end{matrix}\right.\)
6. \(\left\{{}\begin{matrix}x^4-x^3+3x^2-4y-1=0\\\sqrt{\dfrac{x^2+4y^2}{2}}+\sqrt{\dfrac{x^2+2xy+4y^2}{3}}=x+2y\end{matrix}\right.\)
7. \(\left\{{}\begin{matrix}x^3-12z^2+48z-64=0\\y^3-12x^2+48x-64=0\\z^3-12y^2+48y-64=0\end{matrix}\right.\)
giải hệ phương trình sau
\(\left\{{}\begin{matrix}\left(x-2\right)\left(y+1\right)=x.y\\\left(x+8\right)\left(y-2\right)=x.y\end{matrix}\right.\)
1, Giải các hệ phương trình sau
a, \(\left\{{}\begin{matrix}\left(x+y\right)^2-2xy=26\\x+y=6\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}2x^2+x-y=0\\xy+3y-5x=7\end{matrix}\right.\)
c, \(\left\{{}\begin{matrix}\left(x-1\right)^2=1-y\\\left(x^2-y\right)^2=2xy\left(1+x\right)\end{matrix}\right.\)
d, \(\left\{{}\begin{matrix}x^2y+y^2x=2\\x^3+y^3+6=8x^2y^2\end{matrix}\right.\)
Giải hệ phương trình
\(\left\{{}\begin{matrix}6x\left(y^2+z^2\right)=13yz\\3y\left(z^2+x^2\right)=5zx\\6z\left(x^2+y^2\right)=5xy\end{matrix}\right.\)
Giải hệ phương trình:
\(a,\left\{{}\begin{matrix}2x^3+x^2y+2x^2+xy+6=0\\x^2+3x+y=1\end{matrix}\right.\)
\(b,\left\{{}\begin{matrix}x^2=\left(2-y\right)\left(2+y\right)\\2x^3=\left(x+y\right)\left(4-xy\right)\end{matrix}\right.\)
\(c,\left\{{}\begin{matrix}\sqrt[3]{x+2y}=4-x-y\\\sqrt[3]{x+6}+\sqrt{2y}=2\end{matrix}\right.\)
giải hệ phương trình
\(\left\{{}\begin{matrix}\left(x-4\right)\sqrt{y-3}+\left(y-1\right)\sqrt{x+2}=7\sqrt{6}\\12x\sqrt{y-4}+4\sqrt{2}y\sqrt{x-2}=5xy\end{matrix}\right.\)
