Question

Giải phương trình :

6x² + 5\(\sqrt{ }\)2x + 2 = 0

Help me

Answer 1

\(6x^2+5\sqrt{2}x+2=0\)

\(\Leftrightarrow6x^2+3\sqrt{2}x+2\sqrt{2}x+2=0\)

\(\Leftrightarrow3x\left(2x+\sqrt{2}\right)+\sqrt{2}\left(2x+\sqrt{2}\right)=0\)

\(\Leftrightarrow\left(2x+\sqrt{2}\right)\left(3x+\sqrt{2}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+\sqrt{2}=0\\3x+\sqrt{2}=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{\sqrt{2}}{2}\\x=-\dfrac{\sqrt{2}}{3}\end{matrix}\right.\)

Vậy.............