PT (2) là \(2\sqrt{y}\left(1-\dfrac{1}{x+y}\right)=1\) ạ !!!!!!!
PT (2) là \(2\sqrt{y}\left(1-\dfrac{1}{x+y}\right)=1\) ạ !!!!!!!
giải hpt \(\left\{{}\begin{matrix}2\left(x-2\right)^2+\dfrac{1}{\sqrt{y+5}}=3\\\left(x-2\right)^2-\dfrac{2}{\sqrt{y+5}}=-1\end{matrix}\right.\)
10. giải hpt bằng phương pháp thế:
6) \(\left\{{}\begin{matrix}2y-4=0\\3x+y=-4\end{matrix}\right.\)
7) \(\left\{{}\begin{matrix}4x-6y=2\\x-\dfrac{3}{2}y=\dfrac{1}{2}\end{matrix}\right.\)
8) \(\left\{{}\begin{matrix}\dfrac{x}{3}+\dfrac{y}{2}=1\\2x+3y=\dfrac{2}{5}\end{matrix}\right.\)
9) \(\left\{{}\begin{matrix}3x-2=y\\2x+3y=6\end{matrix}\right.\)
10) \(\left\{{}\begin{matrix}2x+3y=2\\4x-y-1=0\end{matrix}\right.\)
11) \(\left\{{}\begin{matrix}3x-2y=3\\2x-\dfrac{4}{3}y=1\end{matrix}\right.\)
12) \(\left\{{}\begin{matrix}5x+y=3\\2x+0,4y=1,2\end{matrix}\right.\)
giúp mk vs ạ mai mk học rồi
Giải hệ phương trình:
a) \(\left\{{}\begin{matrix}2x-y=3\\x+2y=-1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{3}{2}x-y=\dfrac{1}{2}\\3x-2y=1\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}5\left(x+2y\right)=3x-1\\2x+4=3\left(x-5y\right)-12\end{matrix}\right.\)
d) \(\left\{{}\begin{matrix}\dfrac{1}{x}-\dfrac{1}{y}=1\\\dfrac{3}{x}+\dfrac{4}{y}=5\end{matrix}\right.\)
e) \(\left\{{}\begin{matrix}\dfrac{2x}{x+1}+\dfrac{y}{y+1}=\sqrt{2}\\\dfrac{x}{x+1}+\dfrac{3y}{y+1}=-1\end{matrix}\right.\)
Giúp mình với!!!
Giải hpt:
\(\left\{{}\begin{matrix}\dfrac{y^2-x^2}{\sqrt{x-1}}=2y-\sqrt{x-1}\\x^2+y^2=3x-1\end{matrix}\right.\)
Giải HPT: \(\left[{}\begin{matrix}\sqrt{x}\left(1+y\right)=2y\\\sqrt{y}\left(1+z\right)=2z\\\sqrt{z}\left(1+x\right)2x\end{matrix}\right.\)
Giải hệ phương trình:
a)\(\left\{{}\begin{matrix}\dfrac{3x+2}{x-1}-\dfrac{3y-1}{y+2}=0\\\dfrac{2}{x-1}+\dfrac{3}{y+2}=1\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{4x-5}{x+1}+\dfrac{2y-3}{y-5}=8\\\dfrac{3}{x+1}-\dfrac{2}{y-5}=-1\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\dfrac{x+y-2}{x+1}+\dfrac{3-x}{y+1}=\dfrac{5}{4}\\\dfrac{3\left(x+y-2\right)}{x+1}-\dfrac{5-x+2y}{y+1}=\dfrac{3}{4}\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{x-y+1}{x-3}+\dfrac{x+1}{y-3}=\dfrac{-7}{2}\\\dfrac{2\left(x-y+1\right)}{x-3}-\dfrac{x+y-2}{y-3}=-\dfrac{9}{2}\end{matrix}\right.\)
e)\(\left\{{}\begin{matrix}x^2-y^2+2y=1\\\left(x+y\right)^2-2x-2y=0\end{matrix}\right.\)
f)\(\left\{{}\begin{matrix}4x^2+y^2-4xy=4\\x^2+y^2-2\left(xy+8\right)=0\end{matrix}\right.\)
giải hệ phương trình
\(\left\{{}\begin{matrix}\left(xy-2\right)^2+6y=3\left(\dfrac{1}{x}-\dfrac{3}{x^2}\right)\\y^3-4y^2+\dfrac{6}{x}+\left(y-1\right)\sqrt{\left(3y-2\right)}=\dfrac{9}{x^2}\end{matrix}\right.\)
câu 3: giải hệ phương trình
a) \(\left\{{}\begin{matrix}5a+b=5\\b-10a=-19\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{5x}{6}-y=\dfrac{-5}{6}\\\dfrac{2x}{2x+y}+3y=\dfrac{-2}{3}\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}x\sqrt{3}+3y=1\\2x-y\sqrt{3}=\sqrt{3}\end{matrix}\right.\)
d) \(\left\{{}\begin{matrix}\dfrac{1}{x}-\dfrac{6}{y}\\\dfrac{5}{x}+\dfrac{6}{y}=13\end{matrix}\right.=17\)
giúp mk vs ạ mk cần gấp
mn giúp mk bài này với ạ:
Bài 1 giải hệ phương trình:
a) \(\left\{{}\begin{matrix}\left|x+1\right|+\sqrt{y}=5\\\left(x^2+2x+1\right)y=36\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}xy-\dfrac{x}{y}=\dfrac{16}{3}\\xy-\dfrac{y}{x}=\dfrac{9}{2}\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}x+xy+y=0\\x^2+y^2=8\end{matrix}\right.\)
d) \(\left\{{}\begin{matrix}x+y+\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{9}{2}\\xy+\dfrac{1}{xy}=\dfrac{5}{2}\end{matrix}\right.\)
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