cái đề hơi khó hiểu đó
theo đề ra ta có :
\(\left\{{}\begin{matrix}x=10+y\\\frac{160\left(x-y\right)}{xy}=0,8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\\frac{160.10}{\left(10+y\right)y}=0,8\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=10+y\\10y+y^2=\frac{1600}{0,8}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\y^2+10y-2000=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=10+y\\\left(y-40\right)\left(y+50\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\\left[{}\begin{matrix}y=40\\y=-50\end{matrix}\right.\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=40+10=50\\y=40\end{matrix}\right.\\\left\{{}\begin{matrix}x=-50+10=-40\\y=-50\end{matrix}\right.\end{matrix}\right.\)
Vậy .............