\(6x^2-\left(y-5\right)x-y^2+5y-6=0\)
\(\Delta=\left(y-5\right)^2-24\left(-y^2+5y-6\right)=\left(5y-13\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x=\frac{y-5-\left(5y-13\right)}{12}=...\\x=\frac{y-5+\left(5y-13\right)}{12}=...\end{matrix}\right.\)
Thay xuống pt dưới là xong, bạn thay y theo x hay x theo y thì tùy