\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=0\)
\(=>\left\{{}\begin{matrix}\frac{x+1}{10}=0\\\frac{x+1}{11}=0\\\frac{x+1}{12}=0\end{matrix}\right.=>x+1=0\)
=> x = 0 - 1
=> x = -1
a)\(\frac{-3}{2}-2x+\frac{3}{4}=-2\)
b)\(\left(\frac{-2}{3}x-\frac{3}{5}\right)\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\)
c)\(\frac{x}{2}-\left(\frac{3x}{5}-\frac{13}{5}\right)=-\left(\frac{7}{5}+\frac{7}{10}.x\right)\)
d)\(\frac{2x-3}{3}+\frac{-3}{2}=\frac{5-3x}{6}-\frac{1}{3}\)
e)\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}2\right)\)
k)\(\frac{13}{x-1}+\frac{5}{2x-2}-\frac{6}{3x-3}\)
m)\(\left(\frac{3}{2}-\frac{2}{-5}\right):x-\frac{1}{2}=\frac{3}{2}\)
n)\(\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right)\left(2x-2\right)=\left(\frac{-3}{4}+\frac{5}{22}+\frac{3}{26}\right)\)
Giải giúp mk
mk đang cần ghấp trong hôm nay
cám ơn mọi người
Tìm x,biết
a, \(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
Với x ∉ -2,-5,-10,-17
b,\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Với x∉1,3,8,20
c,\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
a) x2+(y-\(\frac{1}{10}\))4=0
b) (\(\frac{1}{2}\)x-5)20+(y-\(\frac{1}{4}\))≤0
a.\(\frac{x+13}{2006}\)+ \(\frac{x+2006}{13}\) + \(\frac{x+1}{2018}\) + 3 = 0
b.\(\frac{4}{\left(x+3\right)\cdot\left(x+7\right)}\) + \(\frac{3}{\left(x+7\right)\cdot\left(x+10\right)}\) = \(\frac{x}{\left(x+3\right)\cdot\left(x+10\right)}\)
mình đang cần rất gấp kết quả mong các bạn giải bài tìm x giúp mình
Các bạn nhớ viết cả lời giải nhé! Thank
tìm x:
a) 3(x-\(\frac{1}{2}\))-5(x+\(\frac{3}{5}\))= -x+\(\frac{1}{5}\)
b)(2x-1) (x+\(\frac{2}{3}\))=0
mọi người giải giúp mình với nhé mình đang cần gấp. Cảm ơn nhé
Tìm x:
a)\(2x\left(x-\frac{1}{7}\right)=0\)
b)\(\frac{1}{2}x+\frac{3}{5}x=\frac{-33}{25}\)
c)\(\left(\frac{2}{3}x-\frac{4}{9}\right)\left(\frac{1}{2}+\frac{-3}{7}:x\right)=0\)
Tìm x,y ϵ Z
a,\(\frac{1}{x}=\frac{1}{6}+\frac{y}{3}\)
b,\(\frac{x}{6}-\frac{1}{y}=\frac{1}{2}\)
c,\(\frac{x}{4}-\frac{1}{y}=\frac{3}{4}\)
d,\(\frac{x}{8}-\frac{2}{y}=\frac{3}{4}\)
e,\(\frac{x}{4}-\frac{2}{y}=\frac{3}{2}\)
g,\(\frac{1}{x}-\frac{1}{y}=\frac{1}{x}.\frac{1}{y}\)
x≠y≠0
Tìm x :
1/ \(\frac{x^7}{81}=27\)
2/ \(\left(x^4\right)^2=\frac{x^{12}}{x^5}\)
3/ \(x^{10}=25.x^8\)
4/ \(\left(3x-1\right)^3=\frac{-8}{27}\)
Tìm x, biết:
a) \(\left(x-\frac{-7}{8}\right)+2,3=3,24\) ; b) \(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\) ; c) |2x-3|+3=16 ; d) \(42+\frac{3}{7}.\left|3x-1\right|=12\)
e) \(\left(x-\frac{1}{2}\right).\left(1+5x\right)=0\) ; f) |2x-1|=|x+2| ; g) \(2.3^x.3^2=18\left(x\in N\right)\) ; h) \(\frac{x+2}{5}=\frac{2-3x}{3}\)
