\(\left(2x-3\right)\left(6-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1,5\\x=3\end{matrix}\right.\)
*\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\Leftrightarrow\frac{1}{3}\cdot\frac{1}{2x-1}=-5-\frac{1}{4}\)
\(\Leftrightarrow\frac{1}{3\left(2x-1\right)}=\frac{-21}{4}\)
\(\Leftrightarrow-63\left(2x-1\right)=4\)
\(\Leftrightarrow2x-1=-\frac{4}{63}\)
\(\Leftrightarrow2x=\frac{59}{63}\)
\(x=\frac{59}{126}\)
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(\Leftrightarrow3x-\frac{3}{2}-5x-3+x-\frac{1}{5}=0\)
\(\Leftrightarrow-x-\frac{47}{10}=0\)
\(\Leftrightarrow-x=\frac{47}{10}\)
\(x=-\frac{47}{10}\)
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\Leftrightarrow\frac{1}{3}:\left(2x-1\right)=\frac{-21}{4}\)
\(\Leftrightarrow2x-1=\frac{-4}{63}\)
\(\Leftrightarrow2x=\frac{59}{63}\)
\(\Leftrightarrow x=\frac{59}{126}\)
Vậy ..........
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(\Leftrightarrow3x-\frac{3}{2}-5x-3+x-\frac{1}{5}=0\)
\(\Leftrightarrow-x-\frac{47}{10}=0\)
\(\Leftrightarrow-x=\frac{47}{10}\)
\(\Leftrightarrow x=\frac{-47}{10}\)
vậy......
\(\left(2x-3\right)\left(6-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=3\\-2x=6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{3}{2}\\x=-3\end{matrix}\right.\)
vậy...