\(\left(3\frac{13}{39}-2\frac{463}{926}\right):\left(-5\frac{13}{39}+2\frac{463}{926}\right)\)
=\(\left(3+\frac{13}{39}-2-\frac{463}{926}\right):\left(-5-\frac{13}{39}+2+\frac{463}{926}\right)\)
=\(\left(3+\frac{1}{3}-2-\frac{1}{2}\right):\left(-5-\frac{1}{3}+2+\frac{1}{2}\right)\)
=\(\frac{5}{6}:\frac{-17}{6}\)
=\(\frac{5.6}{-17.6}\)
=\(\frac{-5}{17}\)
Bài 1: Tính Nhanh
a) \(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)
b) \(\left(8\frac{5}{11}+3\frac{5}{8}\right)-3\frac{5}{11}\)
c) \(-\frac{1}{4}.13\frac{9}{11}-0,25.6\frac{2}{11}\)
d)\(\frac{4}{9}:\left(\frac{-1}{7}\right)+6\frac{5}{9}:\left(\frac{-1}{7}\right)\)
Bài 2: Tìm X
a)\(X:8,25=\left(-2,2\right)\)
b)\(-4\frac{1}{5}.X=2,25\)
c) \(\left(\frac{2X}{5}-1\right):\left(-5\right)=\frac{1}{7}\)
Làm chi tiết hộ em được ko ạ :"< Mai em kiểm tra bài này rùi, mà em ngu lắm á <3
Nhanh hộ em ạ ^^
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(\left(2x-3\right)\left(6-2x\right)=0\)
Tính
a, A=\(\left(\frac{-40}{51}.0,32.\frac{17}{20}\right).\frac{64}{75}\)
b, B=\(4\frac{5}{9}:\left(\frac{-5}{7}\right)-5\frac{4}{9}:\frac{5}{7}\)
c, C= \(1\frac{5}{7}.15+\frac{2}{9}.\left(-15\right)+105.\left(\frac{-2}{3}+\frac{4}{5}-\frac{1}{7}\right)\)
Tìm x biết :
a, \(\frac{1}{3}.x+\frac{2}{5}.\left(x-1\right)=0\)
b,\(3.\left(x-\frac{1}{2}\right)-5.\left(x+\frac{3}{5}\right)=x+\frac{1}{5}\)
b)\(\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
Bài 1:Tính
1)\(\frac{7}{5}+\frac{-8}{5}\) ; 2)\(\frac{-6}{5}\times\frac{15}{24}\) ; 3) \(\left(\frac{2}{3}+1,5\right)-3,5:7\frac{1}{2}\) ; 4)\(\frac{5}{8}-\frac{-7}{9}\) ; 5)\(\frac{-7}{3}\times\frac{12}{28}\).
Bài 2:Tìm x
1)\(x-70=-45\) ; 2)\(\frac{4}{7}:x=\frac{12}{28}\) ; 3)\(\left(\frac{2}{3}x+1,5\right)-3,5:7\frac{1}{2}\) ;
4)x-50=-35 ;5)\(\frac{4}{7}\times x=\frac{11}{28}\) ;6)\(\left(\frac{2}{3}x+2,5\right):2\frac{2}{6}=6\)
m.n ơi!!!
giúp em vs ạ,e đag cần gấp,e sắp thi r
m.n có trước cho e ngày 28/4/2019 nhé :)
Bài 1 : Trên cùng một nữa mặt phẳng bờ chứa tia Ox , vẽ hai tia Ot và Oy sao cho : góc xOt =40\(^0\) ;góc xOy =120\(^0\)
a, Tính số đo góc tOy
b, Vẽ tia On là tia phân giác của góc xOy . Gọi Ox\(^,\) là tia đối của tia Ox. Chứng tỏ tia Oy là tia phân giác của x\(^,\) On.
Bài 2 Cho A=\(\left(\frac{1}{2^2}-1\right)\) .\(\left(\frac{1}{3^2}-1\right)\) .\(\left(\frac{1}{4^2}-1\right)\) ...\(\left(\frac{1}{100^2}-1\right)\) .Hãy so sánh A với \(-\frac{1}{2}\)
Bài 3 Tìm x biết \(\frac{x-1}{9}=\frac{8}{3}\)
bài 2:
a,\(6\frac{4}{5}\)-(\(1\frac{2}{3}\)+\(3\frac{4}{5}\))
b,\(6\frac{5}{7}\)-(\(1\frac{3}{4}\)+\(2\frac{5}{7}\))
c,\(7\frac{5}{9}\)-(\(2\frac{3}{4}\)+\(3\frac{5}{9}\))
d,\(7\frac{5}{11}\)-(\(2\frac{3}{7}\)+\(3\frac{5}{11}\))
e,\(\frac{-3}{5}\).\(\frac{5}{7}\)+\(\frac{-3}{5}\).\(\frac{15}{19}\)+\(\frac{5}{7}\)
f,\(\frac{1}{3}\).\(\frac{4}{5}\)+\(\frac{1}{3}\).\(\frac{6}{5}\)-\(\frac{4}{3}\)
g,\(\frac{4}{19}\).\(\frac{-3}{7}\)+\(\frac{-3}{7}\).\(\frac{15}{19}\)+\(\frac{5}{7}\)
h,\(\frac{5}{9}\).\(\frac{7}{13}\)+\(\frac{5}{9}\).\(\frac{9}{13}\)-\(\frac{5}{9}\).\(\frac{3}{13}\)
mn ơi,giúp mk với ạ,mk cần gấp
bài 1
a,\(\frac{x}{5}\)=\(\frac{2}{3}\)
b,\(\frac{x}{3}\)-\(\frac{1}{2}\)=\(\frac{1}{5}\)
c,\(\frac{x}{5}\)+\(\frac{1}{2}\)=\(\frac{6}{10}\)
d,\(\frac{x+3}{15}\)=\(\frac{1}{3}\)
e,\(\frac{x-12}{4}\)=\(\frac{1}{2}\)
h,\(\frac{4}{5}\)+x=\(\frac{2}{3}\)
i,\(\frac{3}{4}\)-x=\(\frac{1}{3}\)
k,\(\frac{-5}{6}\)-x=\(\frac{2}{3}\)
l,x-\(\frac{5}{9}\)=\(\frac{-2}{3}\)
m,\(\frac{1}{2}\)x+\(\frac{1}{2}\)=\(\frac{5}{2}\)
n,\(\frac{-2}{3}\)-\(\frac{1}{3}\)(2x-5)=\(\frac{3}{2}\)
p,(3x-1)(\(-\frac{1}{2}\)x+5)=0
q,\(3\frac{1}{3}\)+\(\frac{5}{6}\)x=\(3\frac{1}{2}\)
s,\(\frac{1}{2}\)-\(\frac{2}{3}\)x=\(\frac{7}{12}\)
t,\(\frac{3}{4}\)x+\(\frac{1}{5}\)=\(\frac{1}{6}\)
u,\(\frac{3}{8}\)-\(\frac{1}{6}\)x=\(\frac{1}{4}\)
mn ơi'-' xin hãy giúp mk với ạ>^<,mk cần rất gấp,mai nộp r ạ,mong mn giúp mk với ạ:(( huhuhu r mk tik cho:<<