\(CH_4+2O_2\rightarrow CO_2+2H_2O\)
Ta có:
\(n_{CH4}=\frac{6,72}{22,4}=0,3\left(mol\right)\)
\(\Rightarrow n_{CO2}=n_{CH4}=0,3\left(mol\right)\)
\(\Rightarrow n_{CaCO3}=n_{CO2}=0,3\left(mol\right)\)
\(n_{H2O}=0,6\left(mol\right)\)
\(\Rightarrow m_1=m_{CO2}+m_{H2O}=0,3.44+0,6.18=24\left(g\right)\)
\(\Rightarrow m_2=m_{CaCO3}=0,3.100=30\left(g\right)\)