Gọi \(n_{CH_4}=a\left(mol\right);n_{C_2H_6}=b\left(mol\right)\)
\(PTHH:CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
(mol)______a_____2a___a______2a_
\(PTHH:C_2H_6+\frac{7}{2}O_2\underrightarrow{t^o}2CO_2+3H_2O\)
(mol)______b____________2b____3b_
Theo đề bài ta có: \(\left\{{}\begin{matrix}a+b=\frac{10,08}{22,4}\\a+2b=\frac{14,56}{22,4}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,25\\y=0,2\end{matrix}\right.\)
\(\%V_{CH_4}=\frac{0,25.22,4}{10,08}.100\%=55,6\left(\%\right)\Rightarrow\%V_{C_2H_6}=100-55,6=44,4\left(\%\right)\)
\(\sum n_{CO_2}=\frac{14,56}{22,4}=0,65\left(mol\right)\)
\(PTHH:Ba\left(OH\right)_2+CO_2\rightarrow BaCO_3+H_2O\)
(mol)______0,65______0,65_____0,65________
\(m_{\downarrow}=a=0,65.197=128,05\left(g\right)\)