4Al + 3O2 -> 2Al2O3 (1)
2Mg + O2 -> 2MgO (2)
nO2=\(\dfrac{11,2}{22,5}=0,5\left(mol\right)\)
Đặt nAl=a
nMg=b
Ta có:
\(\left\{{}\begin{matrix}27a+24b=20,4\\\dfrac{3}{4}a+\dfrac{1}{2}b=0,5\end{matrix}\right.\)
=>a=b=0,4
mAl=0,4.27=10,8(g)
mMg=20,4-10,8=9,6(g)