H24
26 tháng 9 2020 lúc 22:06
Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
CMR : \(\frac{1}{2}+\frac{1}{3\sqrt{2}}+\frac{1}{4\sqrt{3}}+...+\frac{1}{2020\sqrt{2019}}< 2\)
giải pt : \(\dfrac{1}{\sqrt{x+1}+\sqrt{x+2}}+\dfrac{1}{\sqrt{x+2}+\sqrt{x+3}}+\dfrac{1}{\sqrt{x+3}+\sqrt{x+4}}+...+\dfrac{1}{\sqrt{x+2019}+\sqrt{x+2020}}=11\)
bài 1:
a) D sqrt{2-sqrt{3}}+sqrt{2+sqrt{3}}
b) E sqrt[3]{sqrt{5}-2}+sqrt[3]{sqrt{5}+2}
c) F sqrt[3]{182+sqrt{33125}}+sqrt[3]{182-sqrt{33125}}
bài 2:
a) C frac{1}{sqrt{2}+1}+frac{1}{sqrt{3}+sqrt{2}}+frac{1}{sqrt{4}+sqrt{3}}
b) D frac{3+2sqrt{3}}{sqrt{3}}+frac{2+sqrt{2}}{sqrt{2}+1}-frac{1}{2-sqrt{3}}
c) E frac{3-x^2}{x+sqrt{3}} với xne-sqrt{3}
d) F frac{1}{1+sqrt{2}}+frac{1}{sqrt{2}+sqrt{3}}+...+frac{1}{sqrt{2019}+sqrt{2020}}
e) G sqrt{2+sqrt{2+sqrt{2+sqrt{2+...}}}} (có vô hạn dấu căn)
Đọc tiếp
bài 1:
a) D = \(\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
b) E = \(\sqrt[3]{\sqrt{5}-2}+\sqrt[3]{\sqrt{5}+2}\)
c) F =\(\sqrt[3]{182+\sqrt{33125}}+\sqrt[3]{182-\sqrt{33125}}\)
bài 2:
a) C = \(\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{4}+\sqrt{3}}\)
b) D = \(\frac{3+2\sqrt{3}}{\sqrt{3}}+\frac{2+\sqrt{2}}{\sqrt{2}+1}-\frac{1}{2-\sqrt{3}}\)
c) E =\(\frac{3-x^2}{x+\sqrt{3}}\) với x\(\ne-\sqrt{3}\)
d) F = \(\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+...+\frac{1}{\sqrt{2019}+\sqrt{2020}}\)
e) G = \(\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{2+...}}}}\) (có vô hạn dấu căn)
CMR:
\(\dfrac{\sqrt{3}+\sqrt{4}+\sqrt{5}+\sqrt{6}+\sqrt{8}+\sqrt{10}}{\sqrt{3}+\sqrt{4}+\sqrt{5}}=1+\sqrt{2}\)
CMR:
\(\dfrac{\sqrt[4]{5}+1}{\sqrt[4]{5}-1}=\sqrt[4]{\dfrac{3+2\sqrt[4]{5}}{3-2\sqrt[4]{5}}}\)
CMR: \(\dfrac{\sqrt{4+\sqrt{15}}\left(\sqrt{5}+\sqrt{3}\right)}{\sqrt{2}}=1\)
\(\sqrt{x^2-2x+2018}+2019.\sqrt{x^4+2x^2+2020}=2018\)
Giúp mik vs ạ
Tính a=\(\dfrac{\sqrt[3]{10+6\sqrt{3}}.\left(\sqrt{3}-1\right)}{\sqrt{6+2\sqrt{5}}-5}\)
b, a= \(\sqrt[3]{2-\sqrt{3}}+\sqrt[3]{2+\sqrt{3}}\) CMR \(\dfrac{64}{\left(a^2-3\right)^3}-3a\) ∈ Z
Cho \(x=\dfrac{\sqrt{3}}{\sqrt{\sqrt{3}+1}-1}-\dfrac{\sqrt{3}}{\sqrt{\sqrt{3}+1}+1}\). Tính giá trị của biểu thức:
\(B=\left(x^4-2x^3-x^2+2x-1\right)^{2020}\)