Lời giải:
\(y=\sqrt{1-x^2}\Rightarrow y'=\frac{-2x}{2\sqrt{1-x^2}}=\frac{-x}{\sqrt{1-x^2}}=\frac{-x}{y}\)
\(\Rightarrow y''=\frac{(-x)'.y-(-x).y'}{y^2}=\frac{-y+xy'}{y^2}\)
Do đó:
\(y^2.y''-xy'+y=y^2.\frac{-y+xy'}{y^2}-xy'+y=(-y+xy')-xy'+y=0\)
Ta có đpcm.