Ta có : \(B=8^{10}+32^7=\left(2^3\right)^{10}+\left(2^5\right)^7\)
\(=2^{30}+2^{35}=2^{30}.1+2^{30}.2^5=2^{30}.\left(1+2^5\right)=2^{30}.33⋮33\)
Vậy : B chia hết cho 33
B = 810 + 327
= (23)10 + (25)7
= 230 + 235
= 230.1 + 230. 25
= 230. (1 + 25)
= 230 . 33
Vì 33 \(⋮\)33 => 230. 33 \(⋮\)33.
Chúc bạn học tốt!
\(B=8^{10}+32^7=\left(2^3\right)^{10}+\left(2^5\right)^7=2^{30}+2^{35}\)
\(=2^{30}\left(2^5+1\right)=33.2^{30}\) luôn chia hết cho 33