Do \(0\le x;y;z\le2\Rightarrow\left(2-x\right)\left(2-y\right)\left(2-z\right)+xyz\ge0\)
\(\Leftrightarrow8-4\left(x+y+z\right)+2\left(xy+yz+zx\right)-xyz+xyz\ge0\)
\(\Leftrightarrow xy+yz+zx\ge2\)
Mặt khác \(x+y+z=3\)
\(\Leftrightarrow x^2+y^2+z^2+2\left(xy+yz+zx\right)=9\)
\(\Leftrightarrow x^2+y^2+z^2=9-2\left(xy+yz+zx\right)\le5\)
Dấu "=" xảy ra khi \(\left(x;y;z\right)=\left(0;1;2\right)\) và các hoán vị