Question

Cho x+y=101.Tính giá trị biểu thức:

P=x³-3x²+3x²y+3xy²+y³-3y²-6xy+3x+3y+2017

Answer 1

\(P=\left(x+y\right)^3-3\left(x+y\right)^2+3\left(x+y\right)+2017\)

\(=\left(x+y-1\right)^3+2018\)

\(=100^3+2018\)