Do K đối xứng A qua G nên \(\overrightarrow{AK}=2\overrightarrow{AG}=2\left(\frac{1}{3}\overrightarrow{AB}+\frac{1}{3}\overrightarrow{AC}\right)=\frac{2}{3}\overrightarrow{AB}+\frac{2}{3}\overrightarrow{AC}\)
\(\Rightarrow x=y=\frac{2}{3}\Rightarrow6x+6y=8\)