a: \(\overrightarrow{x}=\overrightarrow{a}+\overrightarrow{b}\)
nên \(\overrightarrow{x}=\left(1+0;-2+3\right)\)
hay \(\overrightarrow{x}=\left(1;1\right)\)
b: \(\overrightarrow{u}=3\cdot\overrightarrow{a}-2\overrightarrow{b}\)
nên \(\overrightarrow{u}=\left(3\cdot1-2\cdot0;-2\cdot3-2\cdot3\right)\)
hay \(\overrightarrow{u}=\left(3;-12\right)\)