Tính C= \(3\dfrac{1}{117}\cdot4\dfrac{1}{119}\cdot-1\dfrac{117}{116}\cdot5\dfrac{115}{119}+\dfrac{5}{119}-\dfrac{10}{117}\)
3*1/117*1/119-4/117*5*118/119-5/117*118+8/39
Chứng minh chia hết :
a, \(328^3+172^3\) chia hết cho 2000
b, \(69^2-69.5\) chia hết cho 32
c, \(19^{19}+69^{19}\) chia hết cho 44
Tính giá trị A= \(3\dfrac{1}{117}.\dfrac{1}{119}-\dfrac{4}{117}.5\dfrac{118}{119}-\dfrac{5}{117.119}+\dfrac{8}{39}\)
\(3\frac{1}{117}.\frac{1}{119}-\frac{4}{117}.5\frac{118}{119}-\frac{5}{117.118}+\frac{3}{39}\)
Chứng minh rằng
A. 8^5+2^11 chia hết cho 17
B.19^19+69^19 chia hết cho 44
b) n2 - 5n - 49 không chia hết cho 69
giải phương trình
a. \(\dfrac{x-3}{113}+\dfrac{x-5}{115}=\dfrac{x-7}{117}+\dfrac{x-9}{119}\)
Giải PT:
a)\(\frac{x-241}{17}+\frac{x-220}{19}+\frac{x-295}{21}+\frac{x-166}{23}=0\)
b)\(\frac{2-x}{2016}-1=\frac{1-x}{2017}-\frac{x}{2018}\)
c)\(\frac{2}{x-1}+\frac{2x+3}{x^2+x+1}=\frac{\left(2x-1\right)\left(2x+1\right)}{x^2-1}\)
d)2x\(^2\)-5x-3=0
