Ta có: \(\dfrac{a}{b}=\dfrac{c}{d}\Leftrightarrow\dfrac{a}{c}=\dfrac{b}{d}\)
\(\Rightarrow\dfrac{2a}{2c}=\dfrac{5b}{5d}=\dfrac{3a}{3c}=\dfrac{4b}{4d}=\dfrac{2a+5b}{2c+5d}=\dfrac{3a-4b}{3c-4d}\)
\(\Rightarrow\dfrac{2a+5b}{3a-4b}=\dfrac{2c+5d}{3c-4d}\) (đpcm)
Chúc bạn học tốt nha
Cho a ; b ; c > 0 và : \(\dfrac{2b+c-a}{a}=\dfrac{2c+a-b}{b}=\dfrac{2a+b-c}{c}\) . Tính :
\(\dfrac{\left(3a-2b\right).\left(3b-2c\right).\left(3c-2a\right)}{abc}\)
Cho : \(\dfrac{2a+b+c+d}{a}=\dfrac{a+2b+c+d}{b}=\dfrac{a+b+2c+d}{c}=\dfrac{a+b+c+2d}{d}\) Tính M biết :
M =\(\dfrac{a+b}{c+d}+\dfrac{b+c}{d+a}+\dfrac{c+d}{a+b}+\dfrac{d+a}{b+c}\)
Biết : \(\dfrac{14bz-15cy}{a}=\dfrac{9cx-7az}{b}=\dfrac{5ay-6bx}{c}\) Cm : \(\dfrac{3x}{a}=\dfrac{5y}{2b}=\dfrac{7z}{3c}\)
cho \(\dfrac{1}{c}\)=\(\dfrac{1}{2}\)\((\dfrac{1}{a}\)+\(\dfrac{1}{b}\))(với a,b,c \(\ne\)0;b\(\ne\)c)
chứng minh rằng \(\dfrac{a}{b}\)=\(\dfrac{a-c}{c-b}\)
Cho :\(\dfrac{a}{b}=\dfrac{c}{d}CMR:\dfrac{ab}{cd}=\dfrac{a^2-b^2}{c^2-d^2}v\text{à}\left(\dfrac{a+b}{c+d}\right)^2=\dfrac{a^2+b^2}{c^2+d^2}\)
Cho b2 = ac; c2 = bd. Với b,c,d khác 0; b+c khác d; b3 + c3 khác d3. Chứng minh rằng \(\dfrac{a^3+b^3-c^3}{b^3+c^3-d^3}=\left(\dfrac{a+b-c}{b+c-d}\right)^3\)
Cho \(\dfrac{3x-2y}{4}=\dfrac{2z-4x}{3}=\dfrac{4y-3z}{2}\)
Chứng minh rằng: \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\)
Help me, please!
Cho : a;b ;c \(\ne\) 0 và khác nhau tm :
\(\dfrac{a}{b+c}=\dfrac{b}{c+a}=\dfrac{c}{a+b}\) . Tính :
P = \(\dfrac{b+c}{a}+\dfrac{c+a}{b}+\dfrac{a+b}{c}\)
Cho a ; b ; c ; x ; y ; z \(\ne\) 0 tm : \(\dfrac{x}{a}=\dfrac{y}{b}=\dfrac{z}{c}\)
CM: \(\dfrac{a^2}{x}+\dfrac{b^2}{y}+\dfrac{c^2}{z}=\dfrac{\left(a+b+c\right)^2}{x+y+z}\)