f(-1)= 2.(-1)2-1.m+n = 15 ➜ n=12+m
f(3)= 2.9+m.3+n = 11
Thay n=12+m vào f(3) ta dc:
18+3m+12+m=11
⇔4m=-19➜m=\(\frac{-19}{4}\)➜n=\(\frac{29}{4}\)
f(x)= 2x2-\(\frac{19}{4}x\)+\(\frac{29}{4}\)
f(1)=\(\frac{9}{2}\)
f(4)=\(\frac{81}{4}\)
\(\frac{f\left(1\right)-f\left(4\right)}{110}=\frac{\frac{9}{2}-\frac{81}{4}}{110}=\frac{-63}{440}\)