a, \(A=\dfrac{1}{1-\sqrt{x}}+\dfrac{1-\sqrt{x}}{\sqrt{x}+1}+\dfrac{1-\sqrt{x}+1+\sqrt{x}}{1-x}\)
\(=\dfrac{\sqrt{x}+1+\left(1-\sqrt{x}\right)+2}{1-x}=\dfrac{4}{1-x}\)
b, \(\dfrac{4}{1-7-4\sqrt{3}}=\dfrac{4}{-6-4\sqrt{3}}=-\dfrac{4}{6+4\sqrt{3}}=\dfrac{-4\left(6-4\sqrt{3}\right)}{-12}=\dfrac{6-4\sqrt{3}}{3}\)